MCQEasyJEE 2024Group 16 Elements

JEE Chemistry 2024 Question with Solution

Given below are two statements: One is labelled as Assertion AA and the other is labelled as Reason RR. Assertion AA: H2{}_2Te is more acidic than H2{}_2S. Reason RR: Bond dissociation enthalpy of H2{}_2Te is lower than H2{}_2S. In light of the above statements, choose the most appropriate from the options given below:

  • A

    Both AA and RR are true but RR is NOT the correct explanation of AA.

  • B

    Both AA and RR are true and RR is the correct explanation of AA.

  • C

    AA is false but RR is true.

  • D

    AA is true but RR is false.

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Assertion AA states that H2{}_2Te is more acidic than H2{}_2S. Reason RR states that the bond dissociation enthalpy of H2{}_2Te is lower than that of H2{}_2S.

Find: Whether Assertion AA and Reason RR are true, and whether RR correctly explains AA.

The solution explains that acidity of binary hydrides increases down the group because the H–X bond becomes weaker as atomic size increases. Thus H2{}_2Te has weaker H–Te bonds than the H–S bonds in H2{}_2S, so it ionizes more easily and behaves as a stronger acid.

It also states that the bond dissociation enthalpy of H2{}_2Te is lower than that of H2{}_2S, which supports easier bond cleavage and therefore greater acidity.

Therefore, both Assertion AA and Reason RR are true, and RR is the correct explanation of AA.

However, the provided the solution also displays "The Correct Option is D," which contradicts the written explanation and the provided correct answer. Based on the actual solution reasoning, the correct option should be B.

Detailed Explanation

Given: Compare the acidity of H2{}_2Te and H2{}_2S, and examine whether lower bond dissociation enthalpy explains the trend.

Find: The correct assertion–reason relationship.

The extracted explanation states the trend of Group 1616 hydrides as:

H2O<H2S<H2Se<H2Te\text{H}_2\text{O} < \text{H}_2\text{S} < \text{H}_2\text{Se} < \text{H}_2\text{Te}

So H2{}_2Te is more acidic than H2{}_2S. This makes Assertion AA true.

The explanation further states that down the group, atomic size increases, orbital overlap with hydrogen becomes poorer, and the H–X bond becomes longer and weaker. Hence the bond dissociation enthalpy decreases.

So for these two hydrides:

Bond strength: H–Te<H–S\text{Bond strength: H–Te} < \text{H–S}

Therefore, the bond dissociation enthalpy of H2{}_2Te is lower than that of H2{}_2S. This makes Reason RR true.

Since lower bond dissociation enthalpy means the proton can be released more easily, RR correctly explains why H2{}_2Te is more acidic than H2{}_2S.

Therefore, both AA and RR are true, and RR is the correct explanation of AA. The correct option is B.

Discrepancy note: the heading in the solution says option D, but the written chemical reasoning clearly supports option B.

Common mistakes

  • Students often compare acidity only using electronegativity. That approach is incomplete here because for hydrides down a group, bond strength becomes the dominant factor. Use the decreasing H–X bond strength trend to judge acidity.

  • A common mistake is to think lower bond dissociation enthalpy means lower acidity. In fact, a weaker H–X bond makes proton release easier, so acidity increases. Relate bond breaking to ease of deprotonation.

  • Some students confuse the acidic trend across a period with the trend down a group. For Group 1616 hydrides, acidity increases down the group from H2{}_2O to H2{}_2Te. Use the correct periodic trend before evaluating the assertion.

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