An alternating voltage volt is applied to a purely resistive load of . The time taken for the current to rise from half of the peak value to the peak value is:
NVAEasyJEE Main 2024 · 30 January, Shift 2Alternating Current Basics
Physics Question from JEE Main 2024 · 30 January, Shift 2
Answer & step-by-step solution
Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.
Practice more Alternating Current Basics questions
Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.
Related questions
- The electric current in the circuit is given as i=i₀(t/T). The r.m.s. current for the period t=0 to t=T is:Easy · JEE 2026
- An inductor stores 16 J of magnetic field energy and dissipates 32 W of thermal energy due to its resistance…Easy · JEE 2026
- An alternating current is given by I = I_A sin ω t + I_B cos ω t. The r.m.s. current will be:Medium · JEE 2025
- Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).…Easy · JEE 2025
- An electric bulb rated as 100 W-220 V is connected to an ac source of rms voltage 220 V. The peak value of…Easy · JEE 2025
- An alternating current is represented by the equation, i=100 √2 sin (100 π t) ampere. The RMS value of…Easy · JEE 2025
