NVAMediumJEE Main 2024 · 30 January, Shift 2Simple Applications

Mathematics Question from JEE Main 2024 · 30 January, Shift 2

Let α=nCkk+1\alpha = \sum \frac{{}^nC_k}{k + 1} and β=(nCknCk+1)k+2\beta = \sum \frac{({}^nC_k \, {}^nC_{k+1})}{k + 2}. If 5α=6β5\alpha = 6\beta, then nn equals:

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