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NVAMediumJEE Main 2024 · 30 January, Shift 2Equation of Line in 3D

Mathematics Question from JEE Main 2024 · 30 January, Shift 2

Let a line passing through the point (−1,2,3)(-1, 2, 3) intersect the lines L1:x−13=y−22=z+1−2L_1: \frac{x-1}{3} = \frac{y-2}{2} = \frac{z+1}{-2} and L2:x+2−3=y−2−2=z−14L_2: \frac{x+2}{-3} = \frac{y-2}{-2} = \frac{z-1}{4} at points M(α,β,γ)M(\alpha, \beta, \gamma) and N(a,b,c)N(a, b, c), respectively. Then the value of (α+β+γ)2(a+b+c)2\frac{(\alpha + \beta + \gamma)^2}{(a + b + c)^2} equals:

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