MCQMediumJEE Main 2024 · 30 January, Shift 1Differentiability

Mathematics Question from JEE Main 2024 · 30 January, Shift 1

Let g:RRg: \mathbb{R} \to \mathbb{R} be a non-constant twice differentiable function such that g(12)=g(32)g'\left(\frac{1}{2}\right) = g'\left(\frac{3}{2}\right). If a real-valued function ff is defined as f(x)=12[g(x)+g(2x)]f(x) = \frac{1}{2}[g(x) + g(2 - x)], then:

  • A

    f(x)=0f''(x) = 0 for at least two xx in (0,2)(0,2)

  • B

    f(x)=0f''(x) = 0 for exactly one xx in (0,1)(0,1)

  • C

    f(x)=0f''(x) = 0 for no xx in (0,1)(0,1)

  • D

    f(32)+f(12)=1f'\left(\frac{3}{2}\right) + f'\left(\frac{1}{2}\right) = 1

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