MCQEasyJEE Main 2024 · 29 January, Shift 2Equilibrium Basics

Chemistry Question from JEE Main 2024 · 29 January, Shift 2

The equilibrium constant for the formation of NH₃ from N₂ and H₂, given [N₂] = 2×102M2\times10^{-2} \, \text{M}, [H₂] = 3×102M3\times10^{-2} \, \text{M}, [NH₃] = 1.5×102M1.5\times10^{-2} \, \text{M} at 500K500 \, \text{K}, is:

  • A

    417417

  • B

    41704170

  • C

    41.741.7

  • D

    4.174.17

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