The correct IUPAC name of K2MnO4 is: — Solution | JEE Chemistry

MCQEasyJEE 2024Ligands & Coordination Number

The correct IUPAC name of $\mathrm{K_2MnO_4}$ is:

Answer

Correct answer:B

Standard Method

Given: The compound is $\mathrm{K_2MnO_4}$ .

Find: The correct IUPAC name of the compound.

First determine the oxidation state of manganese. Potassium has oxidation state $+1$ and oxygen has oxidation state $-2$ .

Using charge balance for the neutral compound:

2(+1) + x + 4(-2) = 0

This simplifies to:

2 + x - 8 = 0

So,

x = +6

Naming Logic

The anion $\mathrm{MnO_4^{2-}}$ is named tetraoxidomanganate(VI) because it contains four oxygens and manganese is in the $+6$ oxidation state.

Adding the cation name gives Potassium tetraoxidomanganate (VI).

Therefore, the correct option is B.

A common mistake is assigning manganese oxidation state $+7$ by confusing $\mathrm{MnO_4^{2-}}$ with permanganate $\mathrm{MnO_4^-}$ . Here the ion has charge $-2$ , so manganese is $+6$ , not $+7$ .
Another mistake is using the older or incorrect name permanganate for this compound. According to IUPAC naming, the correct anion name is tetraoxidomanganate(VI).
Some students include the prefix di for potassium and write dipotassium unnecessarily. For this ionic compound, the cation is written as potassium, followed by the anion name.

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