In Young’s double slit experiment, light from two identical sources is superimposing on a screen. The path dif…

Question

In Young’s double slit experiment, light from two identical sources is superimposing on a screen. The path difference between the two lights reaching a point on the screen is $\frac{7\lambda}{4}$ . The ratio of intensity of the fringe at this point with respect to the maximum intensity of the fringe is:

A
$\frac{1}{2}$
B
$\frac{3}{4}$
C
$\frac{1}{3}$
D
$\frac{1}{4}$

Accepted Answer

A. $$\frac{1}{2}$$

Answer

B. $$\frac{3}{4}$$

Answer

C. $$\frac{1}{3}$$

Answer

D. $$\frac{1}{4}$$

Answer & step-by-step solution

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