Let be the origin, and and be the points on the lines: and , respectively, such that is the shortest distance between the given lines. Then is equal to:
JEE Mathematics 2024 Question with Solution
Answer
Correct answer:9
Step-by-step solution
Standard Method
Given: The points and lie on the lines
and
with as the shortest distance between the lines.
Find:
Parametrize the lines:
Then
The direction vectors are
Their cross product is
Since is the shortest distance between the skew lines, is parallel to . Hence,
So we get
and
Solving these equations,
Therefore,
So,
Now compute the dot product:
Therefore, the value of is .
Shortest Distance Condition in Vector Form
Given: Points and lie on the two given lines, and is the shortest distance between them.
Find:
For the first line, let the common ratio be . Then
which gives
Hence,
For the second line, let the common ratio be . Then
which gives
Hence,
Now,
Using the coordinates listed in the extracted solution, this is written as
The line directions are
Then
For shortest distance between two skew lines, the joining vector is parallel to this cross product. Therefore the corresponding component relations give
and
Subtracting the second equation from the first,
so
Substitute into
to get
Now substitute back:
Therefore,
So the required numerical value is .
Common mistakes
Taking the direction ratios incorrectly from the symmetric form. In , the direction vector is , not . Use the denominators as direction ratios and the constants in numerators to locate a point on the line.
Forgetting the shortest-distance condition. The segment joining the two required points is not arbitrary; it must be parallel to . Do not equate points directly without using this perpendicularity condition.
Making a sign error while parametrizing the second line. From , we get , , . The constants are negative after rearrangement.
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