MCQMediumJEE Main 2024 · 29 January, Shift 2Derivatives of Functions

Mathematics Question from JEE Main 2024 · 29 January, Shift 2

Let y=ln(1x21+x2)y = \ln\left(\frac{1 - x^2}{1 + x^2}\right), 1<x<1-1 < x < 1. Then at x=12x = \frac{1}{2}, the value of 225(yy)225(y' - y'') is equal to:

  • A

    732732

  • B

    746746

  • C

    742742

  • D

    736736

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