MCQMediumJEE Main 2024 · 29 January, Shift 1Derivatives of Functions

Mathematics Question from JEE Main 2024 · 29 January, Shift 1

Suppose f(x)=(2x+2x)tanxtan1(x2x+1)(7x2+3x+1)3f(x) = \frac{\left(2^x + 2^{-x}\right)\tan x \sqrt{\tan^{-1}\left(x^2 - x + 1\right)}}{\left(7x^2 + 3x + 1\right)^3}. The value of f(0)f'(0) is equal to:

  • A

    π\pi

  • B

    00

  • C

    π\sqrt{\pi}

  • D

    π/2\pi/2

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Derivatives of Functions questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions