The distance of the point (2, 3) from the line 2x - 3y + 28 = 0,… | JEE Main 2024 Mathematics PYQ | Jeeify

Log in Start free trial

MCQMediumJEE Main 2024 · 29 January, Shift 2Straight Line Equations

The distance of the point $\left(2, 3\right)$ from the line $2x - 3y + 28 = 0$ , measured parallel to the line $\sqrt{3}x - y + 1 = 0$ , is equal to:

A
$4\sqrt{2}$
B
$6\sqrt{3}$
C
$3 + 4\sqrt{2}$
D
$4 + 6\sqrt{3}$

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Straight Line Equations questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trial More on Straight Line Equations

Related questions