KMnO₄ decomposes on heating at 513 K to form O2 along with: (1) MnO₂ & K₂O₂ (2) K₂MnO₄ & Mn (3) Mn & KO₂ (4) K₂MnO₄ & MnO₂

KMnO₄ decomposes on heating at 513 K to form O2 along with: (1) M… — Solution | JEE Chemistry

MCQEasyJEE 2024Potassium Dichromate & Permanganate

KMnO₄ decomposes on heating at $513 \, \text{K}$ to form $O_2$ along with: (1) MnO₂ & K₂O₂ (2) K₂MnO₄ & Mn (3) Mn & KO₂ (4) K₂MnO₄ & MnO₂

Correct answer:D

Standard Method

Given: Potassium permanganate, $KMnO_4$ , is heated to $513 \, \text{K}$ .

Find: The products formed along with $O_2$ during decomposition.

On heating, potassium permanganate decomposes according to the reaction:

2KMnO_4 \rightarrow K_2MnO_4 + MnO_2 + O_2

Thus, the substances formed along with $O_2$ are $K_2MnO_4$ and $MnO_2$ . Therefore, the correct option is D.

Confusing thermal decomposition of $KMnO_4$ with its redox reactions in acidic medium is incorrect because the products depend on reaction conditions. Here, use the decomposition reaction on heating.
Choosing metallic manganese as a product is wrong because simple heating of $KMnO_4$ at $513 \, \text{K}$ does not reduce manganese to the elemental state. Use the known decomposition products $K_2MnO_4$ and $MnO_2$ instead.

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