The explosive in a Hydrogen bomb is a mixture of ²₁H, ³₁H, and ⁶₃Li in some condensed form. The chain reaction…

Question

The explosive in a Hydrogen bomb is a mixture of $$^2_1	ext{H}$$, $$^3_1	ext{H}$$, and $$^6_3	ext{Li}$$ in some condensed form. The chain reaction is given by:
$$ ^6_3	ext{Li} + ^1_0	ext{n} ightarrow ^4_2	ext{He} + ^3_1	ext{H} $$
$$ ^2_1	ext{H} + ^3_1	ext{H} ightarrow ^4_2	ext{He} + ^1_0	ext{n} $$
[Given: $$M(	ext{Li}) = 6.01690$$ amu, $$M\left(^{2}_{1}	ext{H}ight) = 2.01471$$ amu, $$M\left(^{4}_{2}	ext{He}ight) = 4.00388$$ amu, and $$1$$ amu $$= 931.5$$ MeV]
During the explosion, the energy released is approximately:

Accepted Answer

D. $$22.22 \, 	ext{MeV}$$

Answer

A. $$28.12 \, 	ext{MeV}$$

Answer

B. $$12.64 \, 	ext{MeV}$$

Answer

C. $$16.48 \, 	ext{MeV}$$

Answer & step-by-step solution

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