Physics Question from JEE Main 2023 · 24 January, Shift 2

The energy released per fission of nucleus of $^{240}X$ is $200 \, \text{MeV}$. The energy released if all the atoms in $120 \, \text{g}$ of pure $^{240}X$ undergo fission is $x \times 10^{25} \, \text{MeV}$. The value of $x$ is:

(Given $N_A = 6 \times 10^{23}$)