Physics Question from JEE Main 2024 · 29 January, Shift 1

In the given circuit, the breakdown voltage of the Zener diode is $3.0 \, \text{V}$. What is the value of $I_Z$?

The figure shows: a battery $V = 10 \, \text{V}$ whose positive terminal is connected through a $1 \, \text{k}\Omega$ resistor to node $A$ and whose negative terminal is connected to node $B$. A Zener diode is connected from $A$ down to $B$, and $I_Z$ is the current in this branch. Node $C$ lies on the same conductor as $A$ and node $D$ on the same conductor as $B$, and a $2 \, \text{k}\Omega$ resistor joins $C$ to $D$, so it is in parallel with the Zener diode. The two output terminals of the circuit are drawn at the right-hand ends of the $C$ and $D$ conductors, and nothing is connected across them.