MCQEasyJEE Main 2024 · 27 January, Shift 2Degrees of Freedom & Law of Equipartition

Physics Question from JEE Main 2024 · 27 January, Shift 2

The total kinetic energy of 11 mole of oxygen at 27C27^\circ \text{C} is: (Use the universal gas constant R=8.31J mol1K1R = 8.31 \, \text{J mol}^{-1}\text{K}^{-1})

  • A

    6845.5J6845.5 \, \text{J}

  • B

    5942.0J5942.0 \, \text{J}

  • C

    6232.5J6232.5 \, \text{J}

  • D

    5670.5J5670.5 \, \text{J}

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