The lines (x - 2)/2 = y/(-2) = (z - 7)/16 and (x + 3)/4 = (y + 2)… | JEE Main 2024 Mathematics PYQ

NVAMediumJEE Main 2024 · 27 January, Shift 2Equation of Line in 3D

The lines $\frac{x - 2}{2} = \frac{y}{-2} = \frac{z - 7}{16}$ and $\frac{x + 3}{4} = \frac{y + 2}{3} = \frac{z + 2}{1}$ intersect at the point $P$ . If the distance of $P$ from the line $\frac{x + 1}{2} = \frac{y - 1}{3} = \frac{z - 1}{1}$ is $l$ , then $14l^2$ is equal to:

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