Consider a circle (x - α)² + (y - β)² = 50, where α, β > 0. If th… | JEE Main 2024 Mathematics PYQ

NVAEasyJEE Main 2024 · 27 January, Shift 2Circle Equation & Properties

Consider a circle $(x - \alpha)^2 + (y - \beta)^2 = 50$ , where $\alpha, \beta > 0$ . If the circle touches the line $y + x = 0$ at point $P$ , whose distance from the origin is $4\sqrt{2}$ , then $(\alpha + \beta)^2$ is equal to:

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