MCQMediumJEE 2024Electronic Effects (Inductive, Resonance, Hyperconjugation)

JEE Chemistry 2024 Question with Solution

Which of the following has highly acidic hydrogen?

  • A

    Structure 11

  • B

    Structure 22

  • C

    Structure 33

  • D

    Structure 44

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The question asks which structure has a highly acidic hydrogen.

Find: The correct option containing the most acidic hydrogen.

From the solution, the correct option is D.

The key idea is to compare how stable the conjugate base becomes after removal of a proton. A hydrogen is highly acidic when its removal gives a strongly resonance-stabilized anion.

For structure 44, the methylene group CH2\text{CH}_2 lies between two carbonyl groups C=O\text{C}=\text{O}. On removal of a hydrogen, the resulting negative charge is delocalized over both carbonyl groups by resonance.

CH2 between two carbonyl groups    conjugate base stabilized by resonance\text{CH}_2 \text{ between two carbonyl groups} \; \longrightarrow \; \text{conjugate base stabilized by resonance}

Because the conjugate base is much more stable, the hydrogen in structure 44 is highly acidic.

Therefore, the correct option is D.

Why Structure 4 Is Most Acidic

Given: Acidic hydrogen depends on the stability of the conjugate base formed after deprotonation.

Find: Why structure 44 has highly acidic hydrogen.

In structure 44, the hydrogen is present on a methylene carbon located between two carbonyl groups. After loss of H+\text{H}^+, the carbanion formed is resonance stabilized.

Active methylene compoundremove H+enolate-type conjugate base\begin{aligned} \text{Active methylene compound} &\xrightarrow{\text{remove } \text{H}^+} \text{enolate-type conjugate base} \end{aligned}

The negative charge does not remain localized on one carbon atom. It is delocalized toward both adjacent carbonyl groups, which greatly stabilizes the conjugate base.

This is why hydrogen on an active methylene group between two C=O\text{C}=\text{O} groups is much more acidic than ordinary alkane hydrogens and more acidic than many other common functional group hydrogens.

Hence, structure 44 contains the highly acidic hydrogen, so the correct option is D.

Common mistakes

  • Students often identify acidity only by the presence of an OH-\text{OH} group. This is incorrect because acidity depends on conjugate-base stabilization. Check whether deprotonation gives resonance stabilization, as in the active methylene group of structure 44.

  • A common mistake is to compare the hydrogen atom itself rather than the species formed after its removal. The correct approach is to compare the stability of the conjugate bases formed from each option.

  • Some students miss that a methylene group between two carbonyl groups is unusually acidic. This is wrong because the adjacent carbonyl groups delocalize the negative charge by resonance. Look for electron-withdrawing groups on both sides of the acidic carbon.

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