MCQMediumJEE Main 2024 · 27 January, Shift 1Equation of Line in 3D

Mathematics Question from JEE Main 2024 · 27 January, Shift 1

The distance of the point (7,−2,11)\left(7,-2,11\right) from the line x−61=y−40=z−83\frac{x-6}{1}=\frac{y-4}{0}=\frac{z-8}{3} along the line x−52=y−1−3=z−56\frac{x-5}{2}=\frac{y-1}{-3}=\frac{z-5}{6} is:

  • A

    1212

  • B

    1414

  • C

    1818

  • D

    2121

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