MCQEasyJEE 2023Ionic Equilibria & pH

JEE Chemistry 2023 Question with Solution

Which of the following statement(s) is/are correct?

(A) The pH of 1×108M1 \times 10^{-8}\,\mathrm{M} HCl solution is 88.

(B) The conjugate base of H2PO4\mathrm{H_2PO_4^-} is HPO42\mathrm{HPO_4^{2-}}.

(C) KwK_w increases with increase in temperature.

(D) When a solution of a weak monoprotic acid is titrated against a strong base, at half neutralisation point, pH=12pKa\mathrm{pH}=\dfrac{1}{2}\,pK_a.

Choose the correct answer from the options given below:

  • A

    (A), (B), (C)

  • B

    (B), (C), (D)

  • C

    (B), (C)

  • D

    (A), (D)

Answer

Correct answer:C

Step-by-step solution

Standard Method

Given: Four statements about pH, conjugate base, KwK_w, and weak acid-strong base titration are to be checked.

Find: Which statements are correct and the corresponding correct option.

Statement (A): For very dilute 1×108M1 \times 10^{-8}\,\mathrm{M} HCl, the contribution of H+\mathrm{H^+} from water auto-ionisation cannot be neglected. Therefore, the pH is less than 77, not 88. So statement (A) is incorrect.

Statement (B): The conjugate base is formed by removal of one proton. When H2PO4\mathrm{H_2PO_4^-} loses one H+\mathrm{H^+} ion, it forms HPO42\mathrm{HPO_4^{2-}}. So statement (B) is correct.

Statement (C): Ionisation of water is an endothermic process. Therefore, with increase in temperature, the extent of ionisation increases and hence KwK_w increases. So statement (C) is correct.

Statement (D): At half neutralisation point of a weak acid-strong base titration, the concentration of acid equals that of its conjugate base, and the correct relation is

pH=pKa\mathrm{pH} = pK_a

not

pH=12pKa\mathrm{pH} = \dfrac{1}{2}pK_a

So statement (D) is incorrect.

Therefore, only statements (B) and (C) are correct. The correct option is C.

Elimination Trick

Given: The task is to identify the correct set of statements.

Find: The option that contains only true statements.

A quick elimination works here:

  • Statement (A) is false because extremely dilute HCl does not give pH 88; water auto-ionisation must be considered.
  • Statement (D) is false because at half-neutralisation for a weak acid and strong base titration,
pH=pKa\mathrm{pH} = pK_a

This immediately removes any option containing (A) or (D).

Among the given options, only (B), (C) survives. Hence, the correct option is C.

Common mistakes

  • Assuming that 1×108M1 \times 10^{-8}\,\mathrm{M} HCl must have pH 88 by direct use of pH=log[H+]\mathrm{pH}=-\log[\mathrm{H^+}] is incorrect because the H+\mathrm{H^+} contributed by water auto-ionisation is not negligible at such low concentration. Include water contribution before deciding the pH range.

  • Confusing conjugate acid with conjugate base is a common error. The conjugate base is obtained by removal of one proton, so H2PO4\mathrm{H_2PO_4^-} gives HPO42\mathrm{HPO_4^{2-}}, not a species formed by adding H+\mathrm{H^+}.

  • Memorising the half-neutralisation relation incorrectly as pH=12pKa\mathrm{pH}=\dfrac{1}{2}pK_a leads to the wrong conclusion. For a weak acid-strong base titration, at half-neutralisation the acid and conjugate base concentrations are equal, so use pH=pKa\mathrm{pH}=pK_a instead.

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