MCQEasyJEE 2023LCR Circuits & Resonance

JEE Physics 2023 Question with Solution

Given below are two statements:

Statement I: When the frequency of an a.c. source in a series LCR circuit increases, the current in the circuit first increases, attains a maximum value and then decreases.

Statement II: In a series LCR circuit, the value of the power factor at resonance is one.

In light of the given statements, choose the most appropriate answer from the options given below:

  • A

    Statement I is incorrect but Statement II is true.

  • B

    Both Statement I and Statement II are false.

  • C

    Statement I is correct but Statement II is false.

  • D

    Both Statement I and Statement II are true.

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: Two statements about a series LCR circuit.

Find: Which option correctly identifies the truth values of Statement I and Statement II.

In a series LCR circuit, as the frequency of the a.c. source increases, the impedance changes with frequency. The current therefore first increases, becomes maximum at resonance, and then decreases beyond resonance. So Statement I is correct.

At resonance in a series LCR circuit, the inductive reactance and capacitive reactance become equal, so the circuit behaves as purely resistive. Hence current and voltage are in phase, and the power factor becomes 11. So Statement II is correct.

Therefore, both Statement I and Statement II are true. The correct option is D.

Note: The solution labels the correct option as A, but its explanation clearly concludes that both statements are true, which matches option D in the given options.

Resonance-Based Explanation

Given: A series LCR circuit and two statements regarding current variation with frequency and power factor at resonance.

Find: The correct option.

For a series LCR circuit, current is given by

I=VZI = \frac{V}{Z}

where impedance is

Z=R2+(XLXC)2Z = \sqrt{R^2 + (X_L - X_C)^2}

As frequency changes, XLX_L and XCX_C change, so impedance decreases up to resonance and then increases again. Therefore current rises first, is maximum at resonance, and then falls. Hence Statement I is true.

At resonance,

XL=XCX_L = X_C

so

Z=RZ = R

which is minimum for the series circuit. Then the phase angle is 00, so power factor is

cosϕ=1\cos \phi = 1

Hence Statement II is true.

Therefore, the correct option is D.

Common mistakes

  • Assuming current always decreases when frequency increases. This is wrong because in a series LCR circuit the impedance depends on frequency and becomes minimum at resonance. Check behavior relative to resonance before deciding the current trend.

  • Confusing resonance with maximum impedance. In a series LCR circuit, resonance gives minimum impedance, not maximum impedance. Use XL=XCX_L = X_C to see that the reactive part cancels.

  • Thinking power factor is zero at resonance. That is incorrect for a series LCR circuit because voltage and current are in phase at resonance. Therefore power factor is 11, not 00.

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