MCQEasyJEE 2023Gauss's Law Applications

JEE Physics 2023 Question with Solution

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: If an electric dipole of dipole moment 30×10530 \times 10^{-5} Cm is enclosed by a closed surface, the net flux coming out of the surface will be zero.

Reason R: Electric dipole consists of two equal and opposite charges.

In the light of above statements, choose the correct answer from the options given below:

  • A

    Both A and R are true and R is the correct explanation of A

  • B

    A is true but R is false

  • C

    Both A and R true but R is NOT the correct explanation of A

  • D

    A is false but R is true

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: An electric dipole is enclosed by a closed surface.

Find: Whether the net electric flux through the closed surface is zero, and the correct assertion-reason option.

Using Gauss's law:

Φ=Qinϵ0\Phi = \frac{Q_{\text{in}}}{\epsilon_0}

An electric dipole consists of two equal and opposite charges. Therefore, the total charge enclosed by the closed surface is

Qin=(+q)+(q)=0Q_{\text{in}} = (+q) + (-q) = 0

Hence,

Φ=0ϵ0=0\Phi = \frac{0}{\epsilon_0} = 0

So, Assertion A is true.

Reason R is also true because an electric dipole does consist of two equal and opposite charges.

Further, Reason R correctly explains Assertion A because the net flux depends on the net enclosed charge, which is zero for a dipole.

Therefore, the correct option is A.

Common mistakes

  • Students often think that a non-zero dipole moment must produce non-zero net flux through a closed surface. This is wrong because Gauss's law depends on net enclosed charge, not on dipole moment. Always check the algebraic sum of enclosed charges.

  • A common mistake is to confuse electric field being non-zero at many points on the surface with net flux being non-zero. The field can be non-zero locally, yet the total outward flux can still cancel to zero. Apply Gauss's law to the entire closed surface.

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