In an n-p-n common emitter (CE) transistor, the collector current changes from to for the change in base current from and , respectively. The current gain of the transistor is:
- A
- B
- C
- D
In an n-p-n common emitter (CE) transistor, the collector current changes from to for the change in base current from and , respectively. The current gain of the transistor is:
Correct answer:C
Standard Method
Given: Collector current changes from to , and base current changes from to .
Find: The current gain of the CE transistor.
For a common emitter transistor,
Here,
and
Now substitute the values:
Therefore, the current gain is . The solution working gives , which matches option A even though the solution labels the correct option as C.
Using instead of is incorrect here because the question asks for current gain from the change in currents. Use differences first, then take the ratio.
Ignoring unit conversion between mA and gives a wrong answer. Convert both currents to the same unit before dividing.
Choosing option C only because the solution says so is a source inconsistency. The numerical working clearly gives , so the defensible option is A.
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