MCQMediumJEE Main 2023 · 12 April, Shift 1Simple Applications

Mathematics Question from JEE Main 2023 · 12 April, Shift 1

If

1n+1nCn+1nnCn1++12nC1+nC0=102310\frac{1}{n+1}\,{}^{n}C_{n} + \frac{1}{n}\,{}^{n}C_{n-1} + \dots + \frac{1}{2}\,{}^{n}C_{1} + {}^{n}C_{0} = \frac{1023}{10}

then nn is equal to:

  • A

    66

  • B

    99

  • C

    88

  • D

    77

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