MCQEasyJEE 2023Isothermal & Adiabatic Processes

JEE Physics 2023 Question with Solution

The Thermodynamic process, in which internal energy of the system remains constant is

  • A

    Isobaric

  • B

    Isochoric

  • C

    Adiabatic

  • D

    Isothermal

Answer

Correct answer:D

Step-by-step solution

Standard Method

Given: The thermodynamic process in which internal energy of the system remains constant is to be identified.

Find: Which process has constant internal energy.

For an ideal gas, the change in internal energy is related to temperature by

ΔU=nCvΔT\Delta U = n C_v \Delta T

In an isothermal process, temperature remains constant, so

ΔT=0\Delta T = 0

Therefore,

ΔU=nCv(0)=0\Delta U = n C_v (0) = 0

Hence, internal energy remains constant in an isothermal process.

The correct option is D.

Using Temperature Dependence of Internal Energy

Given:

  • ΔU\Delta U depends on temperature change for an ideal gas.
  • We need the process for which internal energy remains constant.

Find: The correct thermodynamic process.

Identify principle: Internal energy of an ideal gas depends only on temperature.

Apply formula:

ΔU=nCvΔT\Delta U = n C_v \Delta T

where:

  • nn = number of moles
  • CvC_v = molar specific heat at constant volume
  • ΔT\Delta T = change in temperature

In an isothermal process:

ΔT=0\Delta T = 0

Substitute:

ΔU=nCv×0=0\Delta U = n C_v \times 0 = 0

Conclude: Since the change in internal energy is zero, the internal energy remains constant in an isothermal process. Therefore, the correct option is D.

Note: The solution labels the option as A, but its own final explanation states isothermal, which matches option D in the given options.

Common mistakes

  • Confusing adiabatic with constant internal energy. Adiabatic means no heat exchange, not necessarily ΔU=0\Delta U = 0. Use the temperature change relation for internal energy instead.

  • Assuming isochoric implies constant internal energy. Isochoric only means constant volume; internal energy can still change if temperature changes.

  • Ignoring that for an ideal gas, internal energy depends only on temperature. The correct approach is to check which process has ΔT=0\Delta T = 0.

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