MCQMediumJEE Main 2023 · 11 April, Shift 1Electrochemical Cells

Chemistry Question from JEE Main 2023 · 11 April, Shift 1

In an electrochemical reaction of lead, at standard temperature, if E(Pb2+/Pb)=mE^{\circ}(\mathrm{Pb^{2+}/Pb}) = m volt and E(Pb4+/Pb)=nE^{\circ}(\mathrm{Pb^{4+}/Pb}) = n volt, then the value of E(Pb2+/Pb4+)E^{\circ}(\mathrm{Pb^{2+}/Pb^{4+}}) is given by mxnm - xn. The value of xx is _____ (Nearest integer)

  • A

    11

  • B

    22

  • C

    33

  • D

    44

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