MCQMediumJEE Main 2023 · 10 April, Shift 2Trigonometric Equations

Mathematics Question from JEE Main 2023 · 10 April, Shift 2

Let S={x(π2,π2):91tan2x+9tan2x=10}S = \left\{ x \in \left( -\frac{\pi}{2}, \frac{\pi}{2} \right) : 9^{1 - \tan^2 x} + 9^{\tan^2 x} = 10 \right\} and β=xStan2(x3)\beta = \sum_{x \in S} \tan^2 \left( \frac{x}{3} \right), then 16(β14)2\frac{1}{6}\left( \beta - 14 \right)^2 is equal to:

  • A

    1616

  • B

    3232

  • C

    88

  • D

    6464

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