NVAEasyJEE Main 2023 · 1 February, Shift 2Gauss's Law Applications

Physics Question from JEE Main 2023 · 1 February, Shift 2

A cubical volume is bounded by the surfaces x=0x = 0, x=ax = a, y=0y = 0, y=ay = a, z=0z = 0, z=az = a. The electric field in the region is given by E=E0xi^\vec{E} = E_0 x \hat{i}. Where E0=4×104  N C1m1E_0 = 4 \times 10^4 \; \text{N C}^{-1} \text{m}^{-1}. If a=2cma = 2 \, \text{cm}, the charge contained in the cubical volume is Q×1014CQ \times 10^{-14} \, \text{C}. The value of QQ is _____. (Take ϵ0=9×1012C2/N m2\epsilon_0 = 9 \times 10^{-12} \, \text{C}^{2}/\text{N m}^{2})

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