NVAEasyJEE Main 2023 · 1 February, Shift 2Work Done by Force

Physics Question from JEE Main 2023 · 1 February, Shift 2

A force F=5+3y2F = 5 + 3y^{2} acts on a particle in the yy-direction, where FF is newton and yy is in meter. The work done by the force during a displacement from y=2my = 2 \, \text{m} to y=5my = 5 \, \text{m} is _____ J\text{J}.

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