A force F = α + β x² acts on an object in the x-direction. The wo… | JEE Main 2025 Physics PYQ

MCQEasyJEE Main 2025 · 24 January, Shift 1Work Done by Force

A force $F = \alpha + \beta x^2$ acts on an object in the $x$ -direction. The work done by the force is $5 \, \text{J}$ when the object is displaced by $1 \, \text{m}$ . If the constant $\alpha = 1 \, \text{N}$ , then $\beta$ will be:

A
$15 \, \text{N/m}^2$
B
$10 \, \text{N/m}^2$
C
$12 \, \text{N/m}^2$
D
$8 \, \text{N/m}^2$

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