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MCQEasyJEE Main 2023 · 1 February, Shift 1Gauss's Law Applications

Physics Question from JEE Main 2023 · 1 February, Shift 1

Let σ\sigma be the uniform surface charge density of two infinite thin plane sheets shown in the figure. Then the electric fields in three different regions EIE_I, EIIE_{II} and EIIIE_{III} are:

Two parallel infinite thin plane sheets carrying positive surface charge density sigma, with regions I, II, and III marked and separation d shown between the sheets.Two positively charged parallel plane sheets with surface charge density sigma, normal direction indicated, regions I, II, III labeled, and distance d between sheets.
  • A

    E⃗I=2σε0n^,E⃗II=0,E⃗III=2σε0n^\vec{E}_I = \frac{2\sigma}{\varepsilon_0} \hat{n}, \quad \vec{E}_{II} = 0, \quad \vec{E}_{III} = \frac{2\sigma}{\varepsilon_0} \hat{n}

  • B

    E⃗I=0,E⃗II=σε0n^,E⃗III=0\vec{E}_I = 0, \quad \vec{E}_{II} = \frac{\sigma}{\varepsilon_0} \hat{n}, \quad \vec{E}_{III} = 0

  • C

    E⃗I=σ2ε0n^,E⃗II=0,E⃗III=σ2ε0n^\vec{E}_I = \frac{\sigma}{2\varepsilon_0} \hat{n}, \quad \vec{E}_{II} = 0, \quad \vec{E}_{III} = \frac{\sigma}{2\varepsilon_0} \hat{n}

  • D

    E⃗I=−σε0n^,E⃗II=0,E⃗III=σε0n^\vec{E}_I = -\frac{\sigma}{\varepsilon_0} \hat{n}, \quad \vec{E}_{II} = 0, \quad \vec{E}_{III} = \frac{\sigma}{\varepsilon_0} \hat{n}

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