MCQEasyJEE Main 2023 · 1 February, Shift 1Escape Velocity

Physics Question from JEE Main 2023 · 1 February, Shift 1

If Earth has a mass 99 times and radius 22 times that of a planet P, then Ve3xm s1\frac{V_e}{3}\sqrt{x} \, \text{m s}^{-1} will be the minimum velocity required by a rocket to pull out of the gravitational force of P, where VeV_e is escape velocity on Earth. The value of xx is:

  • A

    22

  • B

    33

  • C

    1818

  • D

    11

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