MCQMediumJEE Main 2023 · 31 January, Shift 2Indefinite Integrals

Mathematics Question from JEE Main 2023 · 31 January, Shift 2

Let α>0\alpha > 0. If 0αxx+αxdx=16+20215,\int_{0}^{\alpha} \frac{x}{\sqrt{x + \alpha} - \sqrt{x}} \, dx = \frac{16 + 20\sqrt{2}}{15}, then α\alpha is equal to:

  • A

    22

  • B

    44

  • C

    2\sqrt{2}

  • D

    222\sqrt{2}

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