MCQMediumJEE Main 2026 · 28 January, Shift 1Indefinite Integrals

Mathematics Question from JEE Main 2026 · 28 January, Shift 1

If 15cos2xsin5xcos2xdx=f(x)+C,\int \frac{1-5\cos^2 x}{\sin^5 x\cos^2 x}\,dx=f(x)+C, where CC is the constant of integration, then f ⁣(π6)f ⁣(π4)f\!\left(\frac{\pi}{6}\right)-f\!\left(\frac{\pi}{4}\right) is equal to:

  • A

    13(263)\dfrac{1}{\sqrt{3}}(26-\sqrt{3})

  • B

    13(26+3)\dfrac{1}{\sqrt{3}}(26+\sqrt{3})

  • C

    43(86)\dfrac{4}{\sqrt{3}}(8-\sqrt{6})

  • D

    23(4+6)\dfrac{2}{\sqrt{3}}(4+\sqrt{6})

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Practice more Indefinite Integrals questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Related questions