Jeeify
MCQEasyJEE Main 2023 · 31 January, Shift 1Newton's Second Law & Force

Physics Question from JEE Main 2023 · 31 January, Shift 1

As shown in figure, a 70 kg70 \, \text{kg} garden roller is pushed with a force of F=200 NF = 200 \, \text{N} at an angle of 30∘30^\circ with horizontal. The normal reaction on the roller is: (Given g=10 m/s2g = 10 \, \text{m/s}^2)

A garden roller on a horizontal surface is pushed by force F directed downward at 30 degrees to the horizontal.
  • A

    8002 N800 \sqrt{2} \, \text{N}

  • B

    600 N600 \, \text{N}

  • C

    800 N800 \, \text{N}

  • D

    2003 N200 \sqrt{3} \, \text{N}

Answer & step-by-step solution

Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.

Sign in to see the solution

Practice more Newton's Second Law & Force questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.

Start free trialMore on Newton's Second Law & Force

Related questions