Chemistry Question from JEE Main 2023 · 30 January, Shift 2

1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of $27^\circ \text{C}$. The work done is $3 \, \text{kJ mol}^{-1}$. The final temperature of the gas is ..... $\text{K}$ (Nearest integer). Given $C_v = 20 \, \text{J mol}^{-1} \, \text{K}^{-1}$.