600 mL of 0.01 M HCl is mixed with 400 mL of 0.01 M of H2 SO4. The pH of the mixture is 10^-2. (Nearest integer) Given: 2 = 0.30, 3 = 0.48, 5 = 0.69, 7 = 0.84, 11 = 1.04.

600 mL of 0.01 M HCl is mixed with 400 mL of 0.01 M of H2 SO4. Th… — Solution | JEE Chemistry

NVAMediumJEE 2023Ionic Equilibria & pH

600 mL of $0.01 \, \text{M}$ HCl is mixed with 400 mL of $0.01 \, \text{M}$ of $\text{H}_2\text{SO}_4$ . The pH of the mixture is _____ $\times 10^{-2}$ . (Nearest integer)

Given:

\log 2 = 0.30, \quad \log 3 = 0.48, \quad \log 5 = 0.69, \quad \log 7 = 0.84, \quad \log 11 = 1.04.

Answer

Correct answer:186

Step-by-step solution

the solution unavailable

Given: the solution could not be extracted.

Find: The numerical value asked in the question.

Working could not be extracted from the solution, so the answer has been taken from the provided correct answer field. Therefore, the required value is $186$ .

Common mistakes

Treating $\text{H}_2\text{SO}_4$ as contributing only one $\text{H}^+$ ion is incorrect here. Use its acidic protons appropriately when calculating total hydrogen ion concentration.
Using the original molarities directly after mixing is wrong because the total volume changes. First calculate moles from each acid, then divide by the final volume.
Reporting the pH itself as the answer is incorrect. The question asks for the number in the blank before $\times 10^{-2}$ , so convert the final pH accordingly.

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