JEE Chemistry 2023 Question with Solution

Given: For conversion of compound $A$ $\rightarrow$ $B$, the rate constant is $4.6 \times 10^{-5} \, \text{L mol}^{-1} \, \text{s}^{-1}$.

Find: The order of the reaction.

The unit of the rate constant is given as $\text{L} \, \text{mol}^{-1} \, \text{s}^{-1}$, which corresponds to a second-order reaction. The general formula for the unit of a rate constant is:

$$\text{Unit of } k = \text{(concentration)}^{1-n} \times \text{time}^{-1}$$

where $n$ is the order of the reaction. For $n = 2$, the unit becomes $\text{L} \, \text{mol}^{-1} \, \text{s}^{-1}$.

Therefore, the order of the reaction is $2$.