MCQEasyJEE 2023Carbohydrates (Glucose, Fructose, Sucrose…)

JEE Chemistry 2023 Question with Solution

An indicator ‘X’ is used for studying the effect of variation in concentration of iodide on the rate of reaction of iodide ion with H2O2H_2O_2 at room temperature. The indicator ‘X’ forms blue colored complex with compound ‘A’ present in the solution. The indicator ‘X’ and compound ‘A’ respectively are:

  • A

    Starch and iodine

  • B

    Methyl orange and H2O2H_2O_2

  • C

    Starch and H2O2H_2O_2

  • D

    Methyl orange and iodine

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: The reaction involves iodide ion and H2O2H_2O_2 at room temperature, and indicator ‘X’ forms a blue colored complex with compound ‘A’ present in the solution.

Find: The identities of indicator ‘X’ and compound ‘A’.

In this reaction, iodine I2I_2 is produced as a product when II^- reacts with H2O2H_2O_2. Starch is commonly used as an indicator because it forms a blue-colored complex with iodine.

I+H2O2I2+H2O\text{I}^- + \text{H}_2\text{O}_2 \rightarrow \text{I}_2 + \text{H}_2\text{O}I2+StarchBlue complex\text{I}_2 + \text{Starch} \rightarrow \text{Blue complex}

Thus, the indicator is starch, and the compound forming the blue complex is iodine. The solution states the correct option is B.

Common mistakes

  • Assuming that H2O2H_2O_2 itself gives the blue colour is incorrect, because the blue complex is formed specifically between starch and iodine. Identify the product formed first, then match the indicator behaviour.

  • Confusing methyl orange with starch is incorrect, because methyl orange is an acid-base indicator and does not form the characteristic blue complex in this reaction. Use the known starch-iodine test instead.

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