A null point is found at in a potentiometer when the cell in the secondary circuit is shunted by . When a resistance of is used for shunting, the null point moves to . The internal resistance of the cell is:
NVAMediumJEE Main 2023 · 29 January, Shift 2Potentiometer
Physics Question from JEE Main 2023 · 29 January, Shift 2
Answer & step-by-step solution
Sign in to reveal the correct answer, the full step-by-step solution, and the common mistakes for this question.
Practice more Potentiometer questions
Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step - free to start.
Related questions
- To compare the EMF of two cells using a potentiometer, the balancing lengths obtained are 200 cm and 150 cm.…Medium · JEE 2026
- In the potentiometer, when the cell in the secondary circuit is shunted with 4 Ω resistance, the balance is…Medium · JEE 2026
- In a moving coil galvanometer, two moving coils M₁ and M₂ have the following particulars: R₁ = 5 Ω, N₁ = 15,…Medium · JEE 2025
- The deflection in a moving coil galvanometer falls from 25 divisions to 5 divisions when a shunt of 24 Ω is…Easy · JEE 2024
- With the help of a potentiometer, we can determine the value of the emf of a given cell. The sensitivity of…Easy · JEE 2023
- In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf 1.5 V…Easy · JEE 2023