MCQMediumJEE Main 2023 · 29 January, Shift 2Trigonometric Equations

Mathematics Question from JEE Main 2023 · 29 January, Shift 2

The set of all values of λ\lambda for which the equation cos2(2x)2sin4x2cos2x=λ\cos^2 (2x) - 2\sin^4 x - 2\cos^2 x = \lambda has a solution is:

  • A

    [2,1][-2, -1]

  • B

    [2,32][-2, -\frac{3}{2}]

  • C

    [1,12][-1, -\frac{1}{2}]

  • D

    [32,1][-\frac{3}{2}, -1]

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