MCQMediumJEE 2023Skew Lines & Shortest Distance

JEE Mathematics 2023 Question with Solution

Shortest distance between the lines x12=y+87=z45andx12=y21=z63\frac{x-1}{2} = \frac{y+8}{-7} = \frac{z-4}{5} \quad \text{and} \quad \frac{x-1}{2} = \frac{y-2}{1} = \frac{z-6}{-3} is:

  • A

    232\sqrt{3}

  • B

    434\sqrt{3}

  • C

    333\sqrt{3}

  • D

    535\sqrt{3}

Answer

Correct answer:B

Step-by-step solution

Standard Method

Given: The lines are

x12=y+87=z45\frac{x-1}{2} = \frac{y+8}{-7} = \frac{z-4}{5}

and

x12=y21=z63\frac{x-1}{2} = \frac{y-2}{1} = \frac{z-6}{-3}

Find: The shortest distance between the two lines.

From the symmetric forms, points on the lines can be taken as A(1,8,4)A(1,-8,4) and B(1,2,6)B(1,2,6). Their direction vectors are

p=2i^7j^+5k^,q=2i^+j^3k^\vec{p} = 2\hat{i} - 7\hat{j} + 5\hat{k}, \qquad \vec{q} = 2\hat{i} + \hat{j} - 3\hat{k}

Using the working shown in the solution, the cross product is

p×q=16(i^+j^+k^)\vec{p} \times \vec{q} = 16(\hat{i} + \hat{j} + \hat{k})

so

p×q=163|\vec{p} \times \vec{q}| = 16\sqrt{3}

Also,

AB=(11)i^+(2(8))j^+(64)k^=10j^+2k^\overrightarrow{AB} = (1-1)\hat{i} + (2-(-8))\hat{j} + (6-4)\hat{k} = 10\hat{j} + 2\hat{k}

Hence the shortest distance formula for two skew lines is

d=AB(p×q)p×qd = \frac{|\overrightarrow{AB} \cdot (\vec{p} \times \vec{q})|}{|\vec{p} \times \vec{q}|}

Following the extracted solution working, the computed value is

d=43d = 4\sqrt{3}

Therefore, the shortest distance is 434\sqrt{3} and the correct option is B.

There is a discrepancy between the answer key and the solution. The solution concludes 434\sqrt{3}, which matches option B, so the answer is taken as B.

Checking the Vector Setup

The direction vectors stated in Step 1 of the solution as i^8j^+4k^\hat{i} - 8\hat{j} + 4\hat{k} and i^+2j^+6k^\hat{i} + 2\hat{j} + 6\hat{k} are not the direction vectors of the given lines. From the line equations, the actual direction ratios are read directly as 2,7,5\langle 2,-7,5 \rangle and 2,1,3\langle 2,1,-3 \rangle.

The final value reported in the solution is still 434\sqrt{3}, and that matches option B. Hence, despite the wording inconsistency in the intermediate explanation, the resolved answer from the solution remains B.

Common mistakes

  • Reading the point on the line as the direction vector. In symmetric form, constants like 1,8,41,-8,4 give a point on the line, while 2,7,52,-7,5 give the direction ratios. Use point and direction separately.

  • Using AB|\overrightarrow{AB}| directly as the shortest distance. For skew lines, the correct formula is the projection of AB\overrightarrow{AB} on p×q\vec{p} \times \vec{q}, not the full magnitude of AB\overrightarrow{AB}.

  • Making an error in the cross product. A wrong sign in p×q\vec{p} \times \vec{q} changes the magnitude or projection result. Compute the determinant carefully and then take its magnitude.

Practice more Skew Lines & Shortest Distance questions

Get unlimited AI-adaptive practice, mastery tracking, and an AI tutor that explains every step — free to start.

Related questions