JEE Chemistry 2023 Question with Solution

Given: A TLC glass plate of length $6 \, \text{cm}$ is used for compound $A$.

Find: The retardation factor $R_f$ of compound $A$.

The retardation factor is defined as

$$R_f = \frac{\text{Distance traveled by the solute (A)}}{\text{Distance traveled by the solvent front}}$$

From the solution, the solute travels $3.6 \, \text{cm}$ and the solvent front travels $6 \, \text{cm}$.

$$R_f = \frac{3.6}{6} = 0.6$$

Thus, the retardation factor of compound $A$ is $0.6$.

The expression in the question corresponds to $6 \times 10^{-1}$, which is equal to $0.6$.

Therefore, the final answer is $0.6$.