Let the tangents at the points A() and B() on the circle intersect at the point C. Then the radius of the circle, whose center is C and the line joining A and B is its tangent, is equal to:
- A
- B
- C
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Let the tangents at the points A() and B() on the circle intersect at the point C. Then the radius of the circle, whose center is C and the line joining A and B is its tangent, is equal to:
Correct answer:C
Standard Method
Given: The circle is
and the points are A and B.
Find: The radius of the circle centered at the intersection point C of the tangents at A and B, with AB as a tangent.
From the solution, first complete the square:
So the given circle has center and radius .
The solution then states that the correct option is C. However, its working is internally inconsistent: it computes tangent length from point A, obtains , then suddenly states the required value is , and finally says the correct answer is option (3). Since the solution explicitly declares The Correct Option is C, the answer is taken as C by the stated authority rule.
Therefore, the correct option is C, i.e. the answer is . Note that the solution appears inconsistent with the listed option text.
Treating A and B as external points and using tangent-length formula from those points is wrong, because both points lie on the given circle. A tangent drawn at a point on the circle touches exactly at that point.
Stopping after finding the center and radius of the given circle is insufficient. The question asks for the radius of a different circle centered at C, not the radius of the original circle.
Ignoring contradiction between the option label and the numerical value in the extracted solution can lead to a wrong final choice. Always compare the declared option with the actual listed options and note any mismatch.
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