MCQMediumJEE Main 2023 · 29 January, Shift 1Circle Equation & Properties

Mathematics Question from JEE Main 2023 · 29 January, Shift 1

Let the tangents at the points A((4,11)(4, -11)) and B((8,5)(8, -5)) on the circle x2+y23x+10y15=0x^2 + y^2 - 3x + 10y - 15 = 0 intersect at the point C. Then the radius of the circle, whose center is C and the line joining A and B is its tangent, is equal to:

  • A

    334\frac{3\sqrt{3}}{4}

  • B

    2132\sqrt{13}

  • C

    1313

  • D

    2133\frac{2\sqrt{13}}{3}

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