MCQEasyJEE 2023Gauss's Law Applications

JEE Physics 2023 Question with Solution

Match List I with List II:

Table for match the following question showing List I and List II containing four electromagnetic laws and four integral equations to be matched.

Choose the correct answer from the options given below:

  • A

    A-IV, B-I, C-II, D-III

  • B

    A-I, B-II, C-III, D-IV

  • C

    A-III, B-IV, C-I, D-II

  • D

    A-II, B-III, C-IV, D-I

Answer

Correct answer:A

Step-by-step solution

Standard Method

Given: A matching question on electromagnetic laws and their integral forms.

Find: The correct correspondence between List I and List II.

Using the definitions of the laws:

Gauss's Law of electrostatics

Eds=qϵ0\oint \vec{E} \cdot d\vec{s} = \frac{q}{\epsilon_0}

So A matches IV.

Faraday's law

Edl=dϕBdt\oint \vec{E} \cdot d\vec{l} = -\frac{d\phi_B}{dt}

So B matches I.

Gauss's law of magnetism

BdA=0\oint \vec{B} \cdot d\vec{A} = 0

So C matches II.

Ampere-Maxwell law

Bdl=μ0iC+μ0ϵ0dϕEdt\oint \vec{B} \cdot d\vec{l} = \mu_0 i_C + \mu_0 \epsilon_0 \frac{d\phi_E}{dt}

So D matches III.

Therefore, the correct matching is A-IV, B-I, C-II, D-III.

The solution states "The Correct Option is B", but the worked matching and final answer both give A-IV, B-I, C-II, D-III, which corresponds to option A in the provided options. Hence the defensible correct option is A.

Law Identification by Equation Form

Given: Four named laws and four equations.

Find: Which law corresponds to which integral equation.

Identify each by its characteristic quantity:

  1. If the closed surface integral of electric field equals enclosed charge divided by permittivity,
Eds=qϵ0\oint \vec{E} \cdot d\vec{s} = \frac{q}{\epsilon_0}

it is Gauss's Law in electrostatics.

  1. If the closed line integral of electric field is related to time rate of change of magnetic flux,
Edl=dϕBdt\oint \vec{E} \cdot d\vec{l} = -\frac{d\phi_B}{dt}

it is Faraday's Law.

  1. If the closed surface integral of magnetic field is zero,
BdA=0\oint \vec{B} \cdot d\vec{A} = 0

it is Gauss's Law in magnetism.

  1. If the closed line integral of magnetic field depends on conduction current and displacement current,
Bdl=μ0iC+μ0ϵ0dϕEdt\oint \vec{B} \cdot d\vec{l} = \mu_0 i_C + \mu_0 \epsilon_0 \frac{d\phi_E}{dt}

it is Ampere-Maxwell Law.

Hence,

  • A \to IV
  • B \to I
  • C \to II
  • D \to III

So the correct option is A.

Common mistakes

  • Confusing a closed surface integral with a closed line integral. This is wrong because Gauss laws use surface integrals, while Faraday and Ampere-Maxwell laws use line integrals. First identify whether the equation contains dsd\vec{s} or dAd\vec{A} versus dld\vec{l}.

  • Interchanging the two Gauss laws. This is wrong because electrostatics gives Eds=qϵ0\oint \vec{E} \cdot d\vec{s} = \frac{q}{\epsilon_0}, whereas magnetism gives BdA=0\oint \vec{B} \cdot d\vec{A} = 0. Check both the field symbol and the right-hand side.

  • Missing the negative sign in Faraday's law. This is wrong because electromagnetic induction is represented by dϕBdt-\frac{d\phi_B}{dt}. Use the sign carefully to distinguish it from other Maxwell equations.

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