The minimum value of the function f(x) = ∫₀² e^(|x-t|) dt is: | JEE Main 2023 Mathematics PYQ | Jeeify

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MCQMediumJEE Main 2023 · 25 January, Shift 1Indefinite Integrals

The minimum value of the function $f(x) = \int_{0}^{2} e^{|x-t|} \, dt$ is:

A
$2(e - 1)$
B
$2e - 1$
C
$2$
D
$e(e - 1)$

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