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MCQMediumJEE Main 2023 · 24 January, Shift 2Circle Equation & Properties

Mathematics Question from JEE Main 2023 · 24 January, Shift 2

The locus of the midpoints of the chords of the circle C1:(x−4)2+(y−5)2=4C_1: (x - 4)^2 + (y - 5)^2 = 4, which subtend an angle θi\theta_i at the centre of the circle C1C_1, is a circle of radius rir_i. If θ1=π3\theta_1 = \frac{\pi}{3}, θ3=2π3\theta_3 = \frac{2\pi}{3} and r12=r22+r32r_1^2 = r_2^2 + r_3^2, then θ2\theta_2 is equal to:

  • A

    π4\frac{\pi}{4}

  • B

    3π4\frac{3\pi}{4}

  • C

    π6\frac{\pi}{6}

  • D

    π2\frac{\pi}{2}

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