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MCQMediumJEE Main 2023 · 24 January, Shift 2Simple Applications

Mathematics Question from JEE Main 2023 · 24 January, Shift 2

If (30C1)2+2(30C2)2+3(30C3)2+…+30(30C30)2=α⋅60!(30!)2({}^{30}C_1)^2 + 2({}^{30}C_2)^2 + 3({}^{30}C_3)^2 + \ldots + 30({}^{30}C_{30})^2 = \frac{\alpha \cdot 60!}{(30!)^2}, then α\alpha is equal to:

  • A

    3030

  • B

    6060

  • C

    1515

  • D

    1010

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